◀ Prev · Parts · Full · Next ▶

E R B S ( f ) = 11.17268 ⋅ ⋅ ln ⁡ ⁡ ( 1 + 46.06538 ⋅ ⋅ f f + 14678.49 ) {\displaystyle \mathrm {ERBS} (f)=11.17268\cdot \ln \left(1+{\frac {46.06538\cdot f}{f+14678.49}}\right)} cite-ref-4[4]

f = 676170.4 47.06538 − − e 0.08950404 ⋅ ⋅ E R B S ( f ) − − 14678.49 {\displaystyle f={\frac {676170.4}{47.06538-e^{0.08950404\cdot \mathrm {ERBS} (f)}}}-14678.49} cite-ref-5[5]

where f is in Hz.

Using the linear approximation (Eq.2) for ERB(f) yields:

E R B S ( f ) = 21.4 ⋅ ⋅ log 10 ⁡ ⁡ ( 1 + 0.00437 ⋅ ⋅ f ) {\displaystyle \mathrm {ERBS} (f)=21.4\cdot \log _{10}(1+0.00437\cdot f)} cite-ref-josabel99-6-0[6]

where f is in Hz.

• Critical bands

• Bark scale

cite-note-mooreglasberg-11. ↑ citerefmooreglasberg1983Moore, B.C.J.; Glasberg, B.R. (1983). "Suggested formulae for calculating auditory-filter bandwidths and excitation patterns". Journal of the Acoustical Society of America. 74: 750–753.

cite-note-glasbergmoore-22. ↑ citerefglasbergmoore1990Glasberg, B.R.; Moore, B.C.J. (1990). "Derivation of auditory filter shapes from notched-noise data". Hearing Research. 47 (1–2): 103–138.

◀ Prev · Parts · Full · Next ▶